4(6z-1)-3(z+4)=16(z+1)

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Solution for 4(6z-1)-3(z+4)=16(z+1) equation:


Simplifying
4(6z + -1) + -3(z + 4) = 16(z + 1)

Reorder the terms:
4(-1 + 6z) + -3(z + 4) = 16(z + 1)
(-1 * 4 + 6z * 4) + -3(z + 4) = 16(z + 1)
(-4 + 24z) + -3(z + 4) = 16(z + 1)

Reorder the terms:
-4 + 24z + -3(4 + z) = 16(z + 1)
-4 + 24z + (4 * -3 + z * -3) = 16(z + 1)
-4 + 24z + (-12 + -3z) = 16(z + 1)

Reorder the terms:
-4 + -12 + 24z + -3z = 16(z + 1)

Combine like terms: -4 + -12 = -16
-16 + 24z + -3z = 16(z + 1)

Combine like terms: 24z + -3z = 21z
-16 + 21z = 16(z + 1)

Reorder the terms:
-16 + 21z = 16(1 + z)
-16 + 21z = (1 * 16 + z * 16)
-16 + 21z = (16 + 16z)

Solving
-16 + 21z = 16 + 16z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-16z' to each side of the equation.
-16 + 21z + -16z = 16 + 16z + -16z

Combine like terms: 21z + -16z = 5z
-16 + 5z = 16 + 16z + -16z

Combine like terms: 16z + -16z = 0
-16 + 5z = 16 + 0
-16 + 5z = 16

Add '16' to each side of the equation.
-16 + 16 + 5z = 16 + 16

Combine like terms: -16 + 16 = 0
0 + 5z = 16 + 16
5z = 16 + 16

Combine like terms: 16 + 16 = 32
5z = 32

Divide each side by '5'.
z = 6.4

Simplifying
z = 6.4

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