4(6z-1)-4(z+2)=15(z+1)

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Solution for 4(6z-1)-4(z+2)=15(z+1) equation:


Simplifying
4(6z + -1) + -4(z + 2) = 15(z + 1)

Reorder the terms:
4(-1 + 6z) + -4(z + 2) = 15(z + 1)
(-1 * 4 + 6z * 4) + -4(z + 2) = 15(z + 1)
(-4 + 24z) + -4(z + 2) = 15(z + 1)

Reorder the terms:
-4 + 24z + -4(2 + z) = 15(z + 1)
-4 + 24z + (2 * -4 + z * -4) = 15(z + 1)
-4 + 24z + (-8 + -4z) = 15(z + 1)

Reorder the terms:
-4 + -8 + 24z + -4z = 15(z + 1)

Combine like terms: -4 + -8 = -12
-12 + 24z + -4z = 15(z + 1)

Combine like terms: 24z + -4z = 20z
-12 + 20z = 15(z + 1)

Reorder the terms:
-12 + 20z = 15(1 + z)
-12 + 20z = (1 * 15 + z * 15)
-12 + 20z = (15 + 15z)

Solving
-12 + 20z = 15 + 15z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-15z' to each side of the equation.
-12 + 20z + -15z = 15 + 15z + -15z

Combine like terms: 20z + -15z = 5z
-12 + 5z = 15 + 15z + -15z

Combine like terms: 15z + -15z = 0
-12 + 5z = 15 + 0
-12 + 5z = 15

Add '12' to each side of the equation.
-12 + 12 + 5z = 15 + 12

Combine like terms: -12 + 12 = 0
0 + 5z = 15 + 12
5z = 15 + 12

Combine like terms: 15 + 12 = 27
5z = 27

Divide each side by '5'.
z = 5.4

Simplifying
z = 5.4

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