4(6z-1)-5(z+2)=(z+1)

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Solution for 4(6z-1)-5(z+2)=(z+1) equation:


Simplifying
4(6z + -1) + -5(z + 2) = (z + 1)

Reorder the terms:
4(-1 + 6z) + -5(z + 2) = (z + 1)
(-1 * 4 + 6z * 4) + -5(z + 2) = (z + 1)
(-4 + 24z) + -5(z + 2) = (z + 1)

Reorder the terms:
-4 + 24z + -5(2 + z) = (z + 1)
-4 + 24z + (2 * -5 + z * -5) = (z + 1)
-4 + 24z + (-10 + -5z) = (z + 1)

Reorder the terms:
-4 + -10 + 24z + -5z = (z + 1)

Combine like terms: -4 + -10 = -14
-14 + 24z + -5z = (z + 1)

Combine like terms: 24z + -5z = 19z
-14 + 19z = (z + 1)

Reorder the terms:
-14 + 19z = (1 + z)

Remove parenthesis around (1 + z)
-14 + 19z = 1 + z

Solving
-14 + 19z = 1 + z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1z' to each side of the equation.
-14 + 19z + -1z = 1 + z + -1z

Combine like terms: 19z + -1z = 18z
-14 + 18z = 1 + z + -1z

Combine like terms: z + -1z = 0
-14 + 18z = 1 + 0
-14 + 18z = 1

Add '14' to each side of the equation.
-14 + 14 + 18z = 1 + 14

Combine like terms: -14 + 14 = 0
0 + 18z = 1 + 14
18z = 1 + 14

Combine like terms: 1 + 14 = 15
18z = 15

Divide each side by '18'.
z = 0.8333333333

Simplifying
z = 0.8333333333

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