4(6z-1)-5(z+2)=2(2+1)

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Solution for 4(6z-1)-5(z+2)=2(2+1) equation:


Simplifying
4(6z + -1) + -5(z + 2) = 2(2 + 1)

Reorder the terms:
4(-1 + 6z) + -5(z + 2) = 2(2 + 1)
(-1 * 4 + 6z * 4) + -5(z + 2) = 2(2 + 1)
(-4 + 24z) + -5(z + 2) = 2(2 + 1)

Reorder the terms:
-4 + 24z + -5(2 + z) = 2(2 + 1)
-4 + 24z + (2 * -5 + z * -5) = 2(2 + 1)
-4 + 24z + (-10 + -5z) = 2(2 + 1)

Reorder the terms:
-4 + -10 + 24z + -5z = 2(2 + 1)

Combine like terms: -4 + -10 = -14
-14 + 24z + -5z = 2(2 + 1)

Combine like terms: 24z + -5z = 19z
-14 + 19z = 2(2 + 1)

Combine like terms: 2 + 1 = 3
-14 + 19z = 2(3)

Multiply 2 * 3
-14 + 19z = 6

Solving
-14 + 19z = 6

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + 19z = 6 + 14

Combine like terms: -14 + 14 = 0
0 + 19z = 6 + 14
19z = 6 + 14

Combine like terms: 6 + 14 = 20
19z = 20

Divide each side by '19'.
z = 1.052631579

Simplifying
z = 1.052631579

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