4(7+10)=3(9x-5)+20

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Solution for 4(7+10)=3(9x-5)+20 equation: 



4(7+10)=3(9x-5)+20

We move all terms to the left:

4(7+10)-(3(9x-5)+20)=0

We add all the numbers together, and all the variables

-(3(9x-5)+20)+417=0



We calculate terms in parentheses: -(3(9x-5)+20), so:

3(9x-5)+20

We multiply parentheses

27x-15+20

We add all the numbers together, and all the variables

27x+5

Back to the equation:

-(27x+5)



We get rid of parentheses

-27x-5+417=0

We add all the numbers together, and all the variables

-27x+412=0

We move all terms containing x to the left, all other terms to the right

-27x=-412

x=-412/-27

x=15+7/27

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