4(7+3x)+5(x+2)=72

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Solution for 4(7+3x)+5(x+2)=72 equation: 



4(7+3x)+5(x+2)=72

We move all terms to the left:

4(7+3x)+5(x+2)-(72)=0

We add all the numbers together, and all the variables

4(3x+7)+5(x+2)-72=0

We multiply parentheses

12x+5x+28+10-72=0

We add all the numbers together, and all the variables

17x-34=0

We move all terms containing x to the left, all other terms to the right

17x=34

x=34/17

x=2

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