4(7+4n)=28+n

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Solution for 4(7+4n)=28+n equation: 



4(7+4n)=28+n

We move all terms to the left:

4(7+4n)-(28+n)=0

We add all the numbers together, and all the variables

4(4n+7)-(n+28)=0

We multiply parentheses

16n-(n+28)+28=0

We get rid of parentheses

16n-n-28+28=0

We add all the numbers together, and all the variables

15n=0

n=0/15

n=0

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