4(7+5a)=128

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Solution for 4(7+5a)=128 equation: 



4(7+5a)=128

We move all terms to the left:

4(7+5a)-(128)=0

We add all the numbers together, and all the variables

4(5a+7)-128=0

We multiply parentheses

20a+28-128=0

We add all the numbers together, and all the variables

20a-100=0

We move all terms containing a to the left, all other terms to the right

20a=100

a=100/20

a=5

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