4(7+m)=16+2m

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Solution for 4(7+m)=16+2m equation: 



4(7+m)=16+2m

We move all terms to the left:

4(7+m)-(16+2m)=0

We add all the numbers together, and all the variables

4(m+7)-(2m+16)=0

We multiply parentheses

4m-(2m+16)+28=0

We get rid of parentheses

4m-2m-16+28=0

We add all the numbers together, and all the variables

2m+12=0

We move all terms containing m to the left, all other terms to the right

2m=-12

m=-12/2

m=-6

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