4(7-3a)=-4+4(-5a-2)

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Solution for 4(7-3a)=-4+4(-5a-2) equation: 



4(7-3a)=-4+4(-5a-2)

We move all terms to the left:

4(7-3a)-(-4+4(-5a-2))=0

We add all the numbers together, and all the variables

4(-3a+7)-(-4+4(-5a-2))=0

We multiply parentheses

-12a-(-4+4(-5a-2))+28=0



We calculate terms in parentheses: -(-4+4(-5a-2)), so:

-4+4(-5a-2)

determiningTheFunctionDomain
4(-5a-2)-4

We multiply parentheses

-20a-8-4

We add all the numbers together, and all the variables

-20a-12

Back to the equation:

-(-20a-12)



We get rid of parentheses

-12a+20a+12+28=0

We add all the numbers together, and all the variables

8a+40=0

We move all terms containing a to the left, all other terms to the right

8a=-40

a=-40/8

a=-5

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