4(7-a)-38=16a-5(2+4a)

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Solution for 4(7-a)-38=16a-5(2+4a) equation:


Simplifying
4(7 + -1a) + -38 = 16a + -5(2 + 4a)
(7 * 4 + -1a * 4) + -38 = 16a + -5(2 + 4a)
(28 + -4a) + -38 = 16a + -5(2 + 4a)

Reorder the terms:
28 + -38 + -4a = 16a + -5(2 + 4a)

Combine like terms: 28 + -38 = -10
-10 + -4a = 16a + -5(2 + 4a)
-10 + -4a = 16a + (2 * -5 + 4a * -5)
-10 + -4a = 16a + (-10 + -20a)

Reorder the terms:
-10 + -4a = -10 + 16a + -20a

Combine like terms: 16a + -20a = -4a
-10 + -4a = -10 + -4a

Add '10' to each side of the equation.
-10 + 10 + -4a = -10 + 10 + -4a

Combine like terms: -10 + 10 = 0
0 + -4a = -10 + 10 + -4a
-4a = -10 + 10 + -4a

Combine like terms: -10 + 10 = 0
-4a = 0 + -4a
-4a = -4a

Add '4a' to each side of the equation.
-4a + 4a = -4a + 4a

Combine like terms: -4a + 4a = 0
0 = -4a + 4a

Combine like terms: -4a + 4a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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