4(7-m)=2(8+m)

Solution for 4(7-m)=2(8+m) equation:

4(7-m)=2(8+m)

We move all terms to the left:

4(7-m)-(2(8+m))=0

We add all the numbers together, and all the variables

4(-1m+7)-(2(m+8))=0

We multiply parentheses

-4m-(2(m+8))+28=0


We calculate terms in parentheses: -(2(m+8)), so:

2(m+8)

We multiply parentheses

2m+16

Back to the equation:

-(2m+16)


We get rid of parentheses

-4m-2m-16+28=0

We add all the numbers together, and all the variables

-6m+12=0

We move all terms containing m to the left, all other terms to the right

-6m=-12

m=-12/-6

m=+2