4(7c+1)-47=22c+5

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Solution for 4(7c+1)-47=22c+5 equation: 



4(7c+1)-47=22c+5

We move all terms to the left:

4(7c+1)-47-(22c+5)=0

We multiply parentheses

28c-(22c+5)+4-47=0

We get rid of parentheses

28c-22c-5+4-47=0

We add all the numbers together, and all the variables

6c-48=0

We move all terms containing c to the left, all other terms to the right

6c=48

c=48/6

c=8

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