4(7c+3)=28c+1

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Solution for 4(7c+3)=28c+1 equation: 


Simplifying
4(7c + 3) = 28c + 1

Reorder the terms:
4(3 + 7c) = 28c + 1
(3 * 4 + 7c * 4) = 28c + 1
(12 + 28c) = 28c + 1

Reorder the terms:
12 + 28c = 1 + 28c

Add '-28c' to each side of the equation.
12 + 28c + -28c = 1 + 28c + -28c

Combine like terms: 28c + -28c = 0
12 + 0 = 1 + 28c + -28c
12 = 1 + 28c + -28c

Combine like terms: 28c + -28c = 0
12 = 1 + 0
12 = 1

Solving
12 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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