4(7c+3)=29+2c

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Solution for 4(7c+3)=29+2c equation: 



4(7c+3)=29+2c

We move all terms to the left:

4(7c+3)-(29+2c)=0

We add all the numbers together, and all the variables

4(7c+3)-(2c+29)=0

We multiply parentheses

28c-(2c+29)+12=0

We get rid of parentheses

28c-2c-29+12=0

We add all the numbers together, and all the variables

26c-17=0

We move all terms containing c to the left, all other terms to the right

26c=17

c=17/26

c=17/26

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