4(7r+3)=19

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Solution for 4(7r+3)=19 equation: 



4(7r+3)=19

We move all terms to the left:

4(7r+3)-(19)=0

We multiply parentheses

28r+12-19=0

We add all the numbers together, and all the variables

28r-7=0

We move all terms containing r to the left, all other terms to the right

28r=7

r=7/28

r=1/4

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