4(7x+1)=40+3x

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Solution for 4(7x+1)=40+3x equation: 



4(7x+1)=40+3x

We move all terms to the left:

4(7x+1)-(40+3x)=0

We add all the numbers together, and all the variables

4(7x+1)-(3x+40)=0

We multiply parentheses

28x-(3x+40)+4=0

We get rid of parentheses

28x-3x-40+4=0

We add all the numbers together, and all the variables

25x-36=0

We move all terms containing x to the left, all other terms to the right

25x=36

x=36/25

x=1+11/25

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