4(7x-1)-5(3x-19)=3(4x+4)-1

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Solution for 4(7x-1)-5(3x-19)=3(4x+4)-1 equation: 



4(7x-1)-5(3x-19)=3(4x+4)-1

We move all terms to the left:

4(7x-1)-5(3x-19)-(3(4x+4)-1)=0

We multiply parentheses

28x-15x-(3(4x+4)-1)-4+95=0



We calculate terms in parentheses: -(3(4x+4)-1), so:

3(4x+4)-1

We multiply parentheses

12x+12-1

We add all the numbers together, and all the variables

12x+11

Back to the equation:

-(12x+11)



We add all the numbers together, and all the variables

13x-(12x+11)+91=0

We get rid of parentheses

13x-12x-11+91=0

We add all the numbers together, and all the variables

x+80=0

We move all terms containing x to the left, all other terms to the right

x=-80

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