4(7x-5)+3(x+5)=6(x+3)-(x+10)

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Solution for 4(7x-5)+3(x+5)=6(x+3)-(x+10) equation: 



4(7x-5)+3(x+5)=6(x+3)-(x+10)

We move all terms to the left:

4(7x-5)+3(x+5)-(6(x+3)-(x+10))=0

We multiply parentheses

28x+3x-(6(x+3)-(x+10))-20+15=0



We calculate terms in parentheses: -(6(x+3)-(x+10)), so:

6(x+3)-(x+10)

We multiply parentheses

6x-(x+10)+18

We get rid of parentheses

6x-x-10+18

We add all the numbers together, and all the variables

5x+8

Back to the equation:

-(5x+8)



We add all the numbers together, and all the variables

31x-(5x+8)-5=0

We get rid of parentheses

31x-5x-8-5=0

We add all the numbers together, and all the variables

26x-13=0

We move all terms containing x to the left, all other terms to the right

26x=13

x=13/26

x=1/2

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