4(7x-7)+12/x=13x-4+3

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Solution for 4(7x-7)+12/x=13x-4+3 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*(7*x-7)+12/x = 13*x-4+3 // - 13*x-4+3

4*(7*x-7)-(13*x)+12/x-3+4 = 0

4*(7*x-7)-13*x+12/x-3+4 = 0

(4*x*(7*x-7))/x+(-13*x*x)/x+12/x+(-3*x)/x+(4*x)/x = 0

4*x*(7*x-7)-13*x*x-3*x+4*x+12 = 0

15*x^2-28*x-3*x+4*x+12 = 0

15*x^2-31*x+4*x+12 = 0

15*x^2-27*x+12 = 0

15*x^2-27*x+12 = 0

3*(5*x^2-9*x+4) = 0

5*x^2-9*x+4 = 0

DELTA = (-9)^2-(4*4*5)

DELTA = 1

DELTA > 0

x = (1^(1/2)+9)/(2*5) or x = (9-1^(1/2))/(2*5)

x = 1 or x = 4/5

3*(x-4/5)*(x-1) = 0

(3*(x-4/5)*(x-1))/x = 0

(3*(x-4/5)*(x-1))/x = 0 // * x

3*(x-4/5)*(x-1) = 0

( x-1 )

x-1 = 0 // + 1

x = 1

( x-4/5 )

x-4/5 = 0 // + 4/5

x = 4/5

x in { 1, 4/5 }

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