4(7z+1)=2(10z+16)+20

Solution for 4(7z+1)=2(10z+16)+20 equation:

4(7z+1)=2(10z+16)+20

We move all terms to the left:

4(7z+1)-(2(10z+16)+20)=0

We multiply parentheses

28z-(2(10z+16)+20)+4=0


We calculate terms in parentheses: -(2(10z+16)+20), so:

2(10z+16)+20

We multiply parentheses

20z+32+20

We add all the numbers together, and all the variables

20z+52

Back to the equation:

-(20z+52)


We get rid of parentheses

28z-20z-52+4=0

We add all the numbers together, and all the variables

8z-48=0

We move all terms containing z to the left, all other terms to the right

8z=48

z=48/8

z=6