4(7z+42)=140

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Solution for 4(7z+42)=140 equation:


Simplifying
4(7z + 42) = 140

Reorder the terms:
4(42 + 7z) = 140
(42 * 4 + 7z * 4) = 140
(168 + 28z) = 140

Solving
168 + 28z = 140

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-168' to each side of the equation.
168 + -168 + 28z = 140 + -168

Combine like terms: 168 + -168 = 0
0 + 28z = 140 + -168
28z = 140 + -168

Combine like terms: 140 + -168 = -28
28z = -28

Divide each side by '28'.
z = -1

Simplifying
z = -1

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