4(8-3x)=32-8(x-2)

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Solution for 4(8-3x)=32-8(x-2) equation: 



4(8-3x)=32-8(x-2)

We move all terms to the left:

4(8-3x)-(32-8(x-2))=0

We add all the numbers together, and all the variables

4(-3x+8)-(32-8(x-2))=0

We multiply parentheses

-12x-(32-8(x-2))+32=0



We calculate terms in parentheses: -(32-8(x-2)), so:

32-8(x-2)

determiningTheFunctionDomain
-8(x-2)+32

We multiply parentheses

-8x+16+32

We add all the numbers together, and all the variables

-8x+48

Back to the equation:

-(-8x+48)



We get rid of parentheses

-12x+8x-48+32=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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