4(8-4n)=2(n-40)+4

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Solution for 4(8-4n)=2(n-40)+4 equation: 



4(8-4n)=2(n-40)+4

We move all terms to the left:

4(8-4n)-(2(n-40)+4)=0

We add all the numbers together, and all the variables

4(-4n+8)-(2(n-40)+4)=0

We multiply parentheses

-16n-(2(n-40)+4)+32=0



We calculate terms in parentheses: -(2(n-40)+4), so:

2(n-40)+4

We multiply parentheses

2n-80+4

We add all the numbers together, and all the variables

2n-76

Back to the equation:

-(2n-76)



We get rid of parentheses

-16n-2n+76+32=0

We add all the numbers together, and all the variables

-18n+108=0

We move all terms containing n to the left, all other terms to the right

-18n=-108

n=-108/-18

n=+6

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