4(8-c)=8c+16+6

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Solution for 4(8-c)=8c+16+6 equation: 



4(8-c)=8c+16+6

We move all terms to the left:

4(8-c)-(8c+16+6)=0

We add all the numbers together, and all the variables

4(-1c+8)-(8c+22)=0

We multiply parentheses

-4c-(8c+22)+32=0

We get rid of parentheses

-4c-8c-22+32=0

We add all the numbers together, and all the variables

-12c+10=0

We move all terms containing c to the left, all other terms to the right

-12c=-10

c=-10/-12

c=5/6

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