4(8-c)=8c+20-6c

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Solution for 4(8-c)=8c+20-6c equation: 



4(8-c)=8c+20-6c

We move all terms to the left:

4(8-c)-(8c+20-6c)=0

We add all the numbers together, and all the variables

4(-1c+8)-(2c+20)=0

We multiply parentheses

-4c-(2c+20)+32=0

We get rid of parentheses

-4c-2c-20+32=0

We add all the numbers together, and all the variables

-6c+12=0

We move all terms containing c to the left, all other terms to the right

-6c=-12

c=-12/-6

c=+2

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