4(8b-28)+8=-8(-11b-9)-8

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Solution for 4(8b-28)+8=-8(-11b-9)-8 equation: 



4(8b-28)+8=-8(-11b-9)-8

We move all terms to the left:

4(8b-28)+8-(-8(-11b-9)-8)=0

We multiply parentheses

32b-(-8(-11b-9)-8)-112+8=0



We calculate terms in parentheses: -(-8(-11b-9)-8), so:

-8(-11b-9)-8

We multiply parentheses

88b+72-8

We add all the numbers together, and all the variables

88b+64

Back to the equation:

-(88b+64)



We add all the numbers together, and all the variables

32b-(88b+64)-104=0

We get rid of parentheses

32b-88b-64-104=0

We add all the numbers together, and all the variables

-56b-168=0

We move all terms containing b to the left, all other terms to the right

-56b=168

b=168/-56

b=-3

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