4(8b-28)+8=-8(11b-9)-8

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Solution for 4(8b-28)+8=-8(11b-9)-8 equation: 



4(8b-28)+8=-8(11b-9)-8

We move all terms to the left:

4(8b-28)+8-(-8(11b-9)-8)=0

We multiply parentheses

32b-(-8(11b-9)-8)-112+8=0



We calculate terms in parentheses: -(-8(11b-9)-8), so:

-8(11b-9)-8

We multiply parentheses

-88b+72-8

We add all the numbers together, and all the variables

-88b+64

Back to the equation:

-(-88b+64)



We add all the numbers together, and all the variables

32b-(-88b+64)-104=0

We get rid of parentheses

32b+88b-64-104=0

We add all the numbers together, and all the variables

120b-168=0

We move all terms containing b to the left, all other terms to the right

120b=168

b=168/120

b=1+2/5

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