4(8c-10)+12=-2(3c-10)+13c+2

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Solution for 4(8c-10)+12=-2(3c-10)+13c+2 equation: 



4(8c-10)+12=-2(3c-10)+13c+2

We move all terms to the left:

4(8c-10)+12-(-2(3c-10)+13c+2)=0

We multiply parentheses

32c-(-2(3c-10)+13c+2)-40+12=0



We calculate terms in parentheses: -(-2(3c-10)+13c+2), so:

-2(3c-10)+13c+2

We add all the numbers together, and all the variables

13c-2(3c-10)+2

We multiply parentheses

13c-6c+20+2

We add all the numbers together, and all the variables

7c+22

Back to the equation:

-(7c+22)



We add all the numbers together, and all the variables

32c-(7c+22)-28=0

We get rid of parentheses

32c-7c-22-28=0

We add all the numbers together, and all the variables

25c-50=0

We move all terms containing c to the left, all other terms to the right

25c=50

c=50/25

c=2

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