4(8c-9)=23+5c

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Solution for 4(8c-9)=23+5c equation: 



4(8c-9)=23+5c

We move all terms to the left:

4(8c-9)-(23+5c)=0

We add all the numbers together, and all the variables

4(8c-9)-(5c+23)=0

We multiply parentheses

32c-(5c+23)-36=0

We get rid of parentheses

32c-5c-23-36=0

We add all the numbers together, and all the variables

27c-59=0

We move all terms containing c to the left, all other terms to the right

27c=59

c=59/27

c=2+5/27

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