4(8d-5)+13=12d-2

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Solution for 4(8d-5)+13=12d-2 equation: 



4(8d-5)+13=12d-2

We move all terms to the left:

4(8d-5)+13-(12d-2)=0

We multiply parentheses

32d-(12d-2)-20+13=0

We get rid of parentheses

32d-12d+2-20+13=0

We add all the numbers together, and all the variables

20d-5=0

We move all terms containing d to the left, all other terms to the right

20d=5

d=5/20

d=1/4

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