4(8t+1)-13=t-(t+8)

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Solution for 4(8t+1)-13=t-(t+8) equation:



4(8t+1)-13=t-(t+8)
We move all terms to the left:
4(8t+1)-13-(t-(t+8))=0
We multiply parentheses
32t-(t-(t+8))+4-13=0
We calculate terms in parentheses: -(t-(t+8)), so:
t-(t+8)
We get rid of parentheses
t-t-8
We add all the numbers together, and all the variables
-8
Back to the equation:
-(-8)
We add all the numbers together, and all the variables
32t-1=0
We move all terms containing t to the left, all other terms to the right
32t=1
t=1/32
t=1/32

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