4(8t+1)-13=t-(t+8)

Solution for 4(8t+1)-13=t-(t+8) equation:

4(8t+1)-13=t-(t+8)

We move all terms to the left:

4(8t+1)-13-(t-(t+8))=0

We multiply parentheses

32t-(t-(t+8))+4-13=0


We calculate terms in parentheses: -(t-(t+8)), so:

t-(t+8)

We get rid of parentheses

t-t-8

We add all the numbers together, and all the variables

-8

Back to the equation:

-(-8)


We add all the numbers together, and all the variables

32t-1=0

We move all terms containing t to the left, all other terms to the right

32t=1

t=1/32

t=1/32