4(8y-5)+6(7+y)=136

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Solution for 4(8y-5)+6(7+y)=136 equation: 



4(8y-5)+6(7+y)=136

We move all terms to the left:

4(8y-5)+6(7+y)-(136)=0

We add all the numbers together, and all the variables

4(8y-5)+6(y+7)-136=0

We multiply parentheses

32y+6y-20+42-136=0

We add all the numbers together, and all the variables

38y-114=0

We move all terms containing y to the left, all other terms to the right

38y=114

y=114/38

y=3

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