4(8z-6)+(z-3)=94

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Solution for 4(8z-6)+(z-3)=94 equation: 



4(8z-6)+(z-3)=94

We move all terms to the left:

4(8z-6)+(z-3)-(94)=0

We multiply parentheses

32z+(z-3)-24-94=0

We get rid of parentheses

32z+z-3-24-94=0

We add all the numbers together, and all the variables

33z-121=0

We move all terms containing z to the left, all other terms to the right

33z=121

z=121/33

z=3+2/3

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