4(9/4-12)=(1/4y-4)4

Solution for 4(9/4-12)=(1/4y-4)4 equation:

4(9/4-12)=(1/4y-4)4

We move all terms to the left:

4(9/4-12)-((1/4y-4)4)=0


Domain of the equation: 4y-4)4)!=0

y∈R


We add all the numbers together, and all the variables

-((1/4y-4)4)+1=0

We multiply all the terms by the denominator


-((1+1*4y-4)4)=0


We calculate terms in parentheses: -((1+1*4y-4)4), so:

(1+1*4y-4)4

We add all the numbers together, and all the variables

(1*4y-3)4

We multiply parentheses

16y-12

Back to the equation:

-(16y-12)


We get rid of parentheses

-16y+12=0

We move all terms containing y to the left, all other terms to the right

-16y=-12

y=-12/-16

y=3/4