4(9y-5)=10(3y-17)-30

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Solution for 4(9y-5)=10(3y-17)-30 equation: 



4(9y-5)=10(3y-17)-30

We move all terms to the left:

4(9y-5)-(10(3y-17)-30)=0

We multiply parentheses

36y-(10(3y-17)-30)-20=0



We calculate terms in parentheses: -(10(3y-17)-30), so:

10(3y-17)-30

We multiply parentheses

30y-170-30

We add all the numbers together, and all the variables

30y-200

Back to the equation:

-(30y-200)



We get rid of parentheses

36y-30y+200-20=0

We add all the numbers together, and all the variables

6y+180=0

We move all terms containing y to the left, all other terms to the right

6y=-180

y=-180/6

y=-30

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