4(9y-5)=10(3y-17)-40

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Solution for 4(9y-5)=10(3y-17)-40 equation: 



4(9y-5)=10(3y-17)-40

We move all terms to the left:

4(9y-5)-(10(3y-17)-40)=0

We multiply parentheses

36y-(10(3y-17)-40)-20=0



We calculate terms in parentheses: -(10(3y-17)-40), so:

10(3y-17)-40

We multiply parentheses

30y-170-40

We add all the numbers together, and all the variables

30y-210

Back to the equation:

-(30y-210)



We get rid of parentheses

36y-30y+210-20=0

We add all the numbers together, and all the variables

6y+190=0

We move all terms containing y to the left, all other terms to the right

6y=-190

y=-190/6

y=-31+2/3

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