4(C+1)+2C=7+(C+1)

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Solution for 4(C+1)+2C=7+(C+1) equation:


Simplifying
4(C + 1) + 2C = 7 + (C + 1)

Reorder the terms:
4(1 + C) + 2C = 7 + (C + 1)
(1 * 4 + C * 4) + 2C = 7 + (C + 1)
(4 + 4C) + 2C = 7 + (C + 1)

Combine like terms: 4C + 2C = 6C
4 + 6C = 7 + (C + 1)

Reorder the terms:
4 + 6C = 7 + (1 + C)

Remove parenthesis around (1 + C)
4 + 6C = 7 + 1 + C

Combine like terms: 7 + 1 = 8
4 + 6C = 8 + C

Solving
4 + 6C = 8 + C

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-1C' to each side of the equation.
4 + 6C + -1C = 8 + C + -1C

Combine like terms: 6C + -1C = 5C
4 + 5C = 8 + C + -1C

Combine like terms: C + -1C = 0
4 + 5C = 8 + 0
4 + 5C = 8

Add '-4' to each side of the equation.
4 + -4 + 5C = 8 + -4

Combine like terms: 4 + -4 = 0
0 + 5C = 8 + -4
5C = 8 + -4

Combine like terms: 8 + -4 = 4
5C = 4

Divide each side by '5'.
C = 0.8

Simplifying
C = 0.8

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