4(C+1)+2C=7+3(C-1)

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Solution for 4(C+1)+2C=7+3(C-1) equation: 


Simplifying
4(C + 1) + 2C = 7 + 3(C + -1)

Reorder the terms:
4(1 + C) + 2C = 7 + 3(C + -1)
(1 * 4 + C * 4) + 2C = 7 + 3(C + -1)
(4 + 4C) + 2C = 7 + 3(C + -1)

Combine like terms: 4C + 2C = 6C
4 + 6C = 7 + 3(C + -1)

Reorder the terms:
4 + 6C = 7 + 3(-1 + C)
4 + 6C = 7 + (-1 * 3 + C * 3)
4 + 6C = 7 + (-3 + 3C)

Combine like terms: 7 + -3 = 4
4 + 6C = 4 + 3C

Add '-4' to each side of the equation.
4 + -4 + 6C = 4 + -4 + 3C

Combine like terms: 4 + -4 = 0
0 + 6C = 4 + -4 + 3C
6C = 4 + -4 + 3C

Combine like terms: 4 + -4 = 0
6C = 0 + 3C
6C = 3C

Solving
6C = 3C

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-3C' to each side of the equation.
6C + -3C = 3C + -3C

Combine like terms: 6C + -3C = 3C
3C = 3C + -3C

Combine like terms: 3C + -3C = 0
3C = 0

Divide each side by '3'.
C = 0

Simplifying
C = 0

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