4(J+4)+3=3(28+J)

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Solution for 4(J+4)+3=3(28+J) equation:


Simplifying
4(J + 4) + 3 = 3(28 + J)

Reorder the terms:
4(4 + J) + 3 = 3(28 + J)
(4 * 4 + J * 4) + 3 = 3(28 + J)
(16 + 4J) + 3 = 3(28 + J)

Reorder the terms:
16 + 3 + 4J = 3(28 + J)

Combine like terms: 16 + 3 = 19
19 + 4J = 3(28 + J)
19 + 4J = (28 * 3 + J * 3)
19 + 4J = (84 + 3J)

Solving
19 + 4J = 84 + 3J

Solving for variable 'J'.

Move all terms containing J to the left, all other terms to the right.

Add '-3J' to each side of the equation.
19 + 4J + -3J = 84 + 3J + -3J

Combine like terms: 4J + -3J = 1J
19 + 1J = 84 + 3J + -3J

Combine like terms: 3J + -3J = 0
19 + 1J = 84 + 0
19 + 1J = 84

Add '-19' to each side of the equation.
19 + -19 + 1J = 84 + -19

Combine like terms: 19 + -19 = 0
0 + 1J = 84 + -19
1J = 84 + -19

Combine like terms: 84 + -19 = 65
1J = 65

Divide each side by '1'.
J = 65

Simplifying
J = 65

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