4(Z-3B)=68

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Solution for 4(Z-3B)=68 equation: 


Simplifying
4(Z + -3B) = 68

Reorder the terms:
4(-3B + Z) = 68
(-3B * 4 + Z * 4) = 68
(-12B + 4Z) = 68

Solving
-12B + 4Z = 68

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Add '-4Z' to each side of the equation.
-12B + 4Z + -4Z = 68 + -4Z

Combine like terms: 4Z + -4Z = 0
-12B + 0 = 68 + -4Z
-12B = 68 + -4Z

Divide each side by '-12'.
B = -5.666666667 + 0.3333333333Z

Simplifying
B = -5.666666667 + 0.3333333333Z

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