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4(a+1)=2a+4(1+2a)
We move all terms to the left:
4(a+1)-(2a+4(1+2a))=0
We add all the numbers together, and all the variables
4(a+1)-(2a+4(2a+1))=0
We multiply parentheses
4a-(2a+4(2a+1))+4=0
We calculate terms in parentheses: -(2a+4(2a+1)), so:We get rid of parentheses
2a+4(2a+1)
We multiply parentheses
2a+8a+4
We add all the numbers together, and all the variables
10a+4
Back to the equation:
-(10a+4)
4a-10a-4+4=0
We add all the numbers together, and all the variables
-6a=0
a=0/-6
a=0
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