4(a+2)+1=7a-3(a-2)

Solution for 4(a+2)+1=7a-3(a-2) equation:

Simplifying
4(a + 2) + 1 = 7a + -3(a + -2)

Reorder the terms:
4(2 + a) + 1 = 7a + -3(a + -2)
(2 * 4 + a * 4) + 1 = 7a + -3(a + -2)
(8 + 4a) + 1 = 7a + -3(a + -2)

Reorder the terms:
8 + 1 + 4a = 7a + -3(a + -2)

Combine like terms: 8 + 1 = 9
9 + 4a = 7a + -3(a + -2)

Reorder the terms:
9 + 4a = 7a + -3(-2 + a)
9 + 4a = 7a + (-2 * -3 + a * -3)
9 + 4a = 7a + (6 + -3a)

Reorder the terms:
9 + 4a = 6 + 7a + -3a

Combine like terms: 7a + -3a = 4a
9 + 4a = 6 + 4a

Add '-4a' to each side of the equation.
9 + 4a + -4a = 6 + 4a + -4a

Combine like terms: 4a + -4a = 0
9 + 0 = 6 + 4a + -4a
9 = 6 + 4a + -4a

Combine like terms: 4a + -4a = 0
9 = 6 + 0
9 = 6

Solving
9 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.