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4(a+2)-2a=10+3(a-3
We move all terms to the left:
4(a+2)-2a-(10+3(a-3)=0
We add all the numbers together, and all the variables
-2a+4(a+2)-(10+3(a-3)=0
We multiply parentheses
-2a+4a-(10+3(a-3)+8=0
We add all the numbers together, and all the variables
2a-(10+3(a-3)+8=0
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