4(a+2)-2a=10+3(a-3)1

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Solution for 4(a+2)-2a=10+3(a-3)1 equation: 



4(a+2)-2a=10+3(a-3)1

We move all terms to the left:

4(a+2)-2a-(10+3(a-3)1)=0

We add all the numbers together, and all the variables

-2a+4(a+2)-(10+3(a-3)1)=0

We multiply parentheses

-2a+4a-(10+3(a-3)1)+8=0



We calculate terms in parentheses: -(10+3(a-3)1), so:

10+3(a-3)1

determiningTheFunctionDomain
3(a-3)1+10

We multiply parentheses

3a-9+10

We add all the numbers together, and all the variables

3a+1

Back to the equation:

-(3a+1)



We add all the numbers together, and all the variables

2a-(3a+1)+8=0

We get rid of parentheses

2a-3a-1+8=0

We add all the numbers together, and all the variables

-1a+7=0

We move all terms containing a to the left, all other terms to the right

-a=-7

a=-7/-1

a=+7

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