4(a+2)=14-12(3-2a)

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Solution for 4(a+2)=14-12(3-2a) equation: 



4(a+2)=14-12(3-2a)

We move all terms to the left:

4(a+2)-(14-12(3-2a))=0

We add all the numbers together, and all the variables

4(a+2)-(14-12(-2a+3))=0

We multiply parentheses

4a-(14-12(-2a+3))+8=0



We calculate terms in parentheses: -(14-12(-2a+3)), so:

14-12(-2a+3)

determiningTheFunctionDomain
-12(-2a+3)+14

We multiply parentheses

24a-36+14

We add all the numbers together, and all the variables

24a-22

Back to the equation:

-(24a-22)



We get rid of parentheses

4a-24a+22+8=0

We add all the numbers together, and all the variables

-20a+30=0

We move all terms containing a to the left, all other terms to the right

-20a=-30

a=-30/-20

a=1+1/2

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