4(a+2)=5(a+3)

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Solution for 4(a+2)=5(a+3) equation: 



4(a+2)=5(a+3)

We move all terms to the left:

4(a+2)-(5(a+3))=0

We multiply parentheses

4a-(5(a+3))+8=0



We calculate terms in parentheses: -(5(a+3)), so:

5(a+3)

We multiply parentheses

5a+15

Back to the equation:

-(5a+15)



We get rid of parentheses

4a-5a-15+8=0

We add all the numbers together, and all the variables

-1a-7=0

We move all terms containing a to the left, all other terms to the right

-a=7

a=7/-1

a=-7

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