4(a+2)=6(-a-2)

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Solution for 4(a+2)=6(-a-2) equation: 



4(a+2)=6(-a-2)

We move all terms to the left:

4(a+2)-(6(-a-2))=0

We add all the numbers together, and all the variables

4(a+2)-(6(-1a-2))=0

We multiply parentheses

4a-(6(-1a-2))+8=0



We calculate terms in parentheses: -(6(-1a-2)), so:

6(-1a-2)

We multiply parentheses

-6a-12

Back to the equation:

-(-6a-12)



We get rid of parentheses

4a+6a+12+8=0

We add all the numbers together, and all the variables

10a+20=0

We move all terms containing a to the left, all other terms to the right

10a=-20

a=-20/10

a=-2

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