4(a+2)=7(3-a)

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Solution for 4(a+2)=7(3-a) equation: 



4(a+2)=7(3-a)

We move all terms to the left:

4(a+2)-(7(3-a))=0

We add all the numbers together, and all the variables

4(a+2)-(7(-1a+3))=0

We multiply parentheses

4a-(7(-1a+3))+8=0



We calculate terms in parentheses: -(7(-1a+3)), so:

7(-1a+3)

We multiply parentheses

-7a+21

Back to the equation:

-(-7a+21)



We get rid of parentheses

4a+7a-21+8=0

We add all the numbers together, and all the variables

11a-13=0

We move all terms containing a to the left, all other terms to the right

11a=13

a=13/11

a=1+2/11

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