4(a+2b)+5c=

Solution for 4(a+2b)+5c= equation:

Simplifying
4(a + 2b) + 5c = 0
(a * 4 + 2b * 4) + 5c = 0
(4a + 8b) + 5c = 0

Solving
4a + 8b + 5c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-8b' to each side of the equation.
4a + 8b + -8b + 5c = 0 + -8b

Combine like terms: 8b + -8b = 0
4a + 0 + 5c = 0 + -8b
4a + 5c = 0 + -8b
Remove the zero:
4a + 5c = -8b

Add '-5c' to each side of the equation.
4a + 5c + -5c = -8b + -5c

Combine like terms: 5c + -5c = 0
4a + 0 = -8b + -5c
4a = -8b + -5c

Divide each side by '4'.
a = -2b + -1.25c

Simplifying
a = -2b + -1.25c